x=4x^2+8x-10

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Solution for x=4x^2+8x-10 equation:



x=4x^2+8x-10
We move all terms to the left:
x-(4x^2+8x-10)=0
We get rid of parentheses
-4x^2+x-8x+10=0
We add all the numbers together, and all the variables
-4x^2-7x+10=0
a = -4; b = -7; c = +10;
Δ = b2-4ac
Δ = -72-4·(-4)·10
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{209}}{2*-4}=\frac{7-\sqrt{209}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{209}}{2*-4}=\frac{7+\sqrt{209}}{-8} $

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